2x^2-75x+450=0

Solution for 2x^2-75x+450=0 equation:

2x^2-75x+450=0

a = 2; b = -75; c = +450;
Δ = b2-4ac
Δ = -752-4·2·450
Δ = 2025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2025}=45$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-75)-45}{2*2}=\frac{30}{4}
=7+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-75)+45}{2*2}=\frac{120}{4}
=30
$